Question

The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?

Answer 1

`Q_(net)=4.38\,\,10^(-8)\,C`

Step-by-step explanation:

We use Gauss's Law for the flux over a closed surface equal the net charge inside the closed surface divided the permitivity of space
`\epsilon_0=8.85\,\,10^(-12)\,\,(C^2)/(N*m^2)`

Therefore, by knowing the flux, we can estimate the net charge inside the cubic box with the product:

`\Phi=(Q_(net))/(\epsilon_0) \\Q_(net)=4950\,*\,8.85\,\,10^(-12) \,\,C\\Q_(net)=4.38\,\,10^(-8)\,C`