If f(n)=f(n-1)+8 and f(1)=7, what is f(50)

asked Nov 15, 2018 101k views

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1 vote

$f(n)=f(n-1)+8=f(n-2)+2*8=f(n-3)+3*8=\cdots=f(1)+(n-1)*8$

Since
f(1)=7

, you have

f(50)=f(1)+(50-1)*8=399

Anton Makeev answered Nov 20, 2018

7.8k points

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