Question

Determine the mass in grams of 3.25 mols of glucose(C6H12O6)

Answer 1

Data:
Molar Mass of (C6H12O6)
C = 6*12 = 72 amu
H = 12*1 = 12 amu
O = 6*16 = 96 amu
----------------------------
Molar Mass of (C6H12O6) = 72 + 12 + 96 = 180 g/mol

If:

180 g → 1 mol
y → 3.25 mols

Solving: Rule of three (directly proportional)


`(180)/(y) = (1)/(3.25)`
multiply cross

`1*y = 180*3.25`

`\boxed{\boxed{y = 585\:grams\:of\:glucose}}\end{array}}\qquad\quad\checkmark`