Question

List the angle measures of △VWX in order from smallest to largest. Assume that t is a positive number.

Answer 1

Step-by-step explanation

To begin with, we will first have to obtain the length of side VX

`VX^2=WX^2+VW^2-2* WX* VWcosw`

In our case

`\begin{gathered} WX=28t \\ VW=95t \\ w=94^0 \end{gathered}`

Thus

`\begin{gathered} VX^2=(28t)^2+(95t)^2-2*(28t*95t)cos94 \\ \\ VX^2=784+9025+371.104 \\ VX^2=100180.10 \\ \\ VX=100.90t \end{gathered}`

Next, we will determine the angles at V and X

using sine rule

`\begin{gathered} (sin94)/(100.9t)=(sinV)/(28t) \\ \\ sinV=(28t* sin94)/(100.9t) \\ \\ sinV=0.27683 \\ \\ V=16.07^0 \\ \end{gathered}`

Then, we will get the measure at X

`180^0-16.07^0-94=69.93^0`

Therefore, the order from smallest to largest angles will be

m

OR

m