Question

How to do problem in picture

Answer 1

First find the common multiple, the number that is divisible by 9, 10, and 11.

This is 9*10*11 = 990

Next notice that by using factoring, we can subtract either 9,10,11 and the result will be divisible by that number.


`(9*10*11 -11)/(11) = (11(9*10 -1))/(11) = 9*10 -1`

This works for 10 as well as 9.

Therefore the 3 consecutive integers are:
990-11, 990-10, 990- 9

979, 980, 981