Question

In a butane lighter 9.8g of butane combines with 35.1g of oxygen to form 29.6g carbon dioxide and how many grams of water

Answer 1

To determine the molecular formula of the substance, we can calculate the molar ratios between water, carbon dioxide, and the substance using the given masses. By finding the number of moles of each compound, we can calculate the molecular formula of the substance based on the molar mass.

Step-by-step explanation:

According to the given question, 5 grams of a substance containing hydrogen, carbon, and oxygen were fully combusted and produced 3.00 grams of H₂O and 7.33 grams of CO₂. From these quantities, we can calculate the molar ratios between the substance, water, and carbon dioxide. By using the molar mass of water (18.02 g/mol) and carbon dioxide (44.01 g/mol), we can determine the number of moles of each compound produced in the combustion reaction. Then, using the molar mass of the substance, we can calculate its molecular formula and identify the number of moles of hydrogen, carbon, and oxygen present. By doing this, we can determine the molecular formula of the substance.

Answer 2

if the reacted oxygen is 35.1 g.
H2O mass= (35.1+9.8)-29.6
= 19.3g