Question

Does the graph of the straight line with slope of 5 and y- intercept of -1 pass through the point (1,-2)?

Answer 1

Step-by-step explanation:

Let's plug in the given point (1,-2) into the equation of the line to see if it satisfies the equation:

y = mx + b, where m is the slope and b is the y-intercept.

So, for the given line with slope 5 and y-intercept -1, the equation would be:

y = 5x - 1

Now, let's plug in (1,-2) into the equation:

-2 = 5(1) - 1

Simplifying, we get:

-2 = 4

This is not true, so the point (1,-2) does not lie on the line with slope 5 and y-intercept -1. Therefore, the answer is no, the graph of the line does not pass through the point (1,-2).

Answer 2

The answer is: "No."
_____________________________
Step-by-step explanation:
_____________________________

Given: y = 5x - 1 ;

is: (1, -2) a solution?
______________________________
When "x" = 1, does "y" = -2 ?
______________________________
5*(-2) - 1 = -10 - 1 = -11 . No.
_________________________________
So, the answer is: No.
__________________________________