Question

Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0

o,one    25,two    30,one

which of the 3 is the answer

Answer 1

I hope this helps you



1.y^2+3y-4 =0


a=1


b=3


c= -4


disctirminant=b^2-4ac



disctirminant=3^2-4.1.(-4)


disctirminant=9+16


disctirminant=25