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Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner.
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Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner.

User Sean Copenhaver
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I believe that if you multiply 120 x 45 you would get 5,400 why? Because when a problem has "of" means to multiply.

So... the vacuum cleaner is 5,400 percent efficient :)

Sorry if it's wrong I'm only in fifth grade
User Lint
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