Question

Yea I can see if it works if it’s okay

Answer 1

We want to find the derivative of

`y=sin(1.2t-3.7)`

(a) So, using chain rule, the inside function is u,

we have the inside:

`u=1.2t-3.7`

outside becomes

`y=sin(u)`

(b) The derivative of

inside, we have

`(du)/(dt)=1.2`

derivative of the outside, we have

`(dy)/(du)=cos(u)`

chain rule we have

`\begin{gathered} (dy)/(dt)=(dy)/(du)*(du)/(dt) \\ =cos(u)*1.2 \\ =cos(1.2t-3.7)*1.2 \end{gathered}`

Hence the answer is

`(dy)/(dt)=1.2cos(1.2t-3.7)`