90.1k views
0 votes
Solve the system of equations by elimination. 2x−y+3z=−12x−y+3z=−1 x+2y−4z=−1x+2y−4z=−1 y−2z=0y−2z=0

1 Answer

5 votes
the solution is
x=0 , y=0 , z=0

User Jck
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories