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In the two digit number x,both the sum and the difference of its digit is 6. What is the value of x ?

User Not Amused
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1 Answer

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Let
a be the first digit and
b the second. Then the number is
x=10a+b. The sum and difference of the two digits is 6, which means


\begin{cases}a+b=6\\a-b=6\end{cases}\implies a=6,b=0

which means the number is
x=6*10+0=60
User WalterM
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