Question

Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).

a.
x + 1 = 5(y + 3)
c.
y + 1 = 5(x + 3)
b.
y + 1 = -1/5(x + 3)
d.
y + 3 = -1/5(x + 1)

Answer 1

The answer is B

Write an equation for the line perpendicular to y = 5x – 12
that contains (–3, –1).
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The given equation has slope = 5
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The desired equation must have slope = -1/5
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Form: y = mx + b
Solve for "b" when m = -1/5 and y = -1 when x = -3

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-1 = (-1/5)(-3) + b
-1 = (3/5) + b
b = -8/5
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Answer=y + 1 = 5(x + 3)

Answer 2

y = 5x - 12
Here, slope = 5
Perpendicular line slope = -1/5 [ opposite and reciprocal ]

Now, y - y1 = m(x - x1)
y + 1 = -1/5 (x + 3)

In short, Your Answer would be Option B

Hope this helps!