Question

What is the volume of the cone rounded to the nearest tenth? The diagram is not drawn to scale. The height of the cone is 19 yd.A) 2646.3 yd^3B) 1462.4 yd^3C) 1039.0 yd^3D) 975.0 yd^3

Answer 1

To find the volume of the cone rounded to the nearest tenth

we have that,

Volume of the cone (V) is,

`(1)/(3)\pi r^2h`

where r is the radius and h is the height of the cone.

Given that,

r=7 yd

h=19 yd

Substitute the values we get,

`V=(1)/(3)\pi(7)^2*19`

we get,

`V=(931)/(3)\pi`

we know that pi is approximately equal to 3.14, Substitute the value we get,

`V=(931)/(3)(3.14)`

we get,

`V=974.446\approx975\text{ yd}^3`

Answer is: Option D:

`\begin{equation*} 975\text{ yd}^3 \end{equation*}`