Answer:
y = 3x + 4
Explanation:
A parallel line has the same slope as the reference line.
y = mx + b (m is the slope and b is the y-intercept)
The reference line, y = 3x + 2, has a slope of 3.
We need another line of the form y = 3x + b, So all we need is a new b. Any value we choose for b will result in a straight line. But our line needs to go through point (2,10), so we need a specific value for b that will move the line to the appropriate position.
We can find b by entering the point and solving for b:
y = 3x + b (2,10)
10 = 3*(2) + b
b = 4
The equation becomes y = 3x + 4