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X^3+y^3=3axy find dy/dx

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x^3+y^3=3axy

(\mathrm d)/(\mathrm dx)\left[x^3+y^3\right]=(\mathrm d)/(\mathrm dx)[3axy]

3x^2+3y^2(\mathrm dy)/(\mathrm dx)=3a\left(y+x(\mathrm dy)/(\mathrm dx)\right)

\left(3y^2-3ax\right)(\mathrm dy)/(\mathrm dx)=3ay-3x^2

(\mathrm dy)/(\mathrm dx)=(3ay-3x^2)/(3y^2-3ax)

(\mathrm dy)/(\mathrm dx)=(ay-x^2)/(y^2-ax)
User Harry Lime
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