Question

Calculate the kinetic energy of a 3.15 kg bowling ball rolling down the lane at 2.5 m/s. Include the units.

Answer 1

Given:

The mass of the ball is: m = 3.15 kg

The velocity of the ball is: v = 2.5 m/s

To find:

The kinetic energy of the ball.

Step-by-step explanation:

The kinetic energy is the energy that a particle has when is is in motion. For the particle of mass m moving with velocity v, the kinetic energy KE is given as:

`KE=(1)/(2)mv^2`

Substitute the values in the above expression, we get:

`\begin{gathered} KE=(1)/(2)*3.15\text{ kg}*(2.5\text{ m/s\rparen}^2 \\ \\ KE=(1)/(2)*3.15\text{ kg}*6.25\text{ m}^2\text{/s}^2 \\ \\ KE=9.84\text{ kg.m}^2\text{/s}^2 \\ \\ KE=9.84\text{ J} \end{gathered}`

Final answer:

The kinetic energy of the ball is 9.84 J.