Question

If a 4 kg ball is dropped from rest and falls without air resistance, what is its speed after 0.5 seconds?

Answer 1

4.9 m/s

Step-by-step explanation:

The velocity of the ball after 5 seconds can be calculated using the following equation

`v_f=v_i+at`

vi = the initial velocity, in this case, it is equal to 0 because the ball is dropped from the rest

a = acceleration, this is the acceleration due to gravity so it is -9.8 m/s²

t = time, it is equal to 0.5 s

So, replacing the values, we get:

`\begin{gathered} v_f=0-9.8(0.5) \\ v_f=-4.9\text{ m/s} \end{gathered}`

Therefore, the speed after 0.5 seconds is 4.9 m/s