Question

A jet engine applies a force of 300 N horizontally to the right against a 50 kg rocket. The force of air friction 200 N. If the rocket is thrust horizontally 2.0 m, the kinetic energy gained by the rocket is

Answer 1

We will have the following:

`(300N)(2m)+(-200N)(2m)=200J`

Then, we from the work-kinetic force theorem we will have that the total kinetic energy gained by the rocket was 200 Joules.