Question

A ball starts to roll up a slope with a slope with a velocity of 5m/s and comes to a stop after rolling 5.0m up the slope. Assume acceleration was uniform.

a) What was the rate of acceleration of the ball on the slope?

Answer 1

The rate of acceleration of the ball on the slope, assuming uniform acceleration, is -2.5 m/s². This value signifies a deceleration as the ball moves up the slope.

Step-by-step explanation:

To find the rate of acceleration of the ball as it goes up the slope, we can use the kinematic equation: v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the displacement. Since the ball comes to a stop, we set v = 0 m/s and know that u = 5 m/s and s = 5.0 m. Plugging these values into the equation gives us:

0 = (5 m/s)² + 2a(5.0 m)

25 m²/s² = -10a m

a = -2.5 m/s²

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, thus it's a deceleration.

Answer 2

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