Question

If the moles and volume of a gas are held constant, dropping the temperature from 40 degrees Celsius to 20 degrees Celsius causes would cause an initial pressure of 3 atmospheres to drop to 1.5 atmospheres.

T/F

Answer 1

It would cause a drop but I am not sure double check other answers

Answer 2

False.

Step-by-step explanation:

Hello,

In this case, as the moles are held constant, one uses the Gay-Lussac's law in order to relate both the temperature and the pressure at the beginning and at the end of the experiment via the following relationship:

`P_1T_2=P_2T_1`

By solving for the pressure at the second (final) state we can substantiate whether the 1.5 atm are correct as shown below:

`P_2=(P_1T_2)/(T_1)=(3atm*293.15K)/(313.15K)= 2.8 atm`

Therefore, even when the pressure is correctly decreased, the given value is wrong as 2.8 atm is the correct final pressure, in this manner, the statement is false.

Best regards.