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The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How long will it take for the population of the bacteria to reach 800?

2 Answers

3 votes

The answer is to this problem would be 10.8.

User Harry Beasant
by
6.3k points
2 votes

Answer:

16.34 hours

Explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula


A=P(2)^(t)/(24)

Here A =800 is the amount that is needed to reach

P is the initial amount that is 500

We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get


800=500(2)^(t)/(24)

On simplification we get


\Rightarrow(8)/(5)=(2)^(t)/(24)

Taking log on both sides we get


\Rightarrow\log(8)/(5)=\log(2)^(t)/(24)

using
\log(m)/(n)=\log m-\log n

And
\log a^m=m\log a


\Rightarrow\log{8}-\log{5}=(t)/(24)\log2

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get


\Rightarrow 0.903-0.698=(t)/(24)0.301


\Rightarrow 0.205=(t)/(24)0.301


\Rightarrow (0.205)/(0.301)\cdot 24=t


\Rightarrow t=16.34

User Neetika
by
6.4k points
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