Question

Use the quadratic formula to solve 2w²+w=5

Answer 1

2w²+w=5
⇒2w²+w-5 = 0
here a=2, b=1 and c = -5


`x = (-b \pm \ (b^2-4ac) )/(2a) \\ \\ \Rightarrow x = (-1 \pm \ √((1)^2-4*2*(-5)) )/(2*2) \\ \\ \Rightarrow x = (-1 \pm \ √(1+40) )/(2*2) \\ \\ \Rightarrow x= (-1+ √(41) )/(4) \ and\ (-1- √(41) )/(4)`