Question

4. -X2 + 10 5x + 3 5x+3 6r 4x2 + 2x - 7 I need the perimeter.

Answer 1

The perimeter is the sum of all sides, therefore:

`\begin{gathered} P=(5x+3)+(4x^2+2x-7)+(-x^2+10)+(5x+3) \\ add_{\text{ }}like_{\text{ }}terms\colon \\ (5x+5x+2x)+(4x^2-x^2)+(3+3+10-7) \\ 3x^2+12x+9 \end{gathered}`
`\begin{gathered} 3x^2+12x+9 \\ (1)/(3)(3x^2+12x+9)=x^2+4x+3 \end{gathered}`

The factors of 3 that sum to 4 are 3 and 1. So:

`x^2+4x+3=(x+3)(x+1)`