Answer:
The line of the equation in the point-slope form of the line passing through the point (4, -2) and having slope 2 will be:
![y+2=4(x-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/uj52jae516f1ij49qyrhxzzfdtl6opo479.png)
Please check the attached graph.
Explanation:
Given
Point slope form:
![y-y_1=m\left(x-x_1\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/59wu8ly47al9vwq2ng2tgmsrx1lo1l4azh.png)
where
- m is the slope of the line
In our case:
m = 4
The point (x₁, y₁) = (4, -2)
substituting the values m = 4 and the point (x₁, y₁) = (4, -2) in the point-slope form of the line equation
![y-y_1=m\left(x-x_1\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/59wu8ly47al9vwq2ng2tgmsrx1lo1l4azh.png)
![y - (-2) = 4(x-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/yw7zx2n9idkyb7vseh6vtxepwiafg0l03m.png)
![y+2=4(x-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/uj52jae516f1ij49qyrhxzzfdtl6opo479.png)
Thus, the line of the equation in the point-slope form of the line passing through the point (4, -2) and having slope 2 will be:
![y+2=4(x-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/uj52jae516f1ij49qyrhxzzfdtl6opo479.png)
Please check the attached graph.