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Calculate the number of moles of Barium hydroxide, Ba(OH)2, present in a 100.0 g sample.

User Imagist
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1 Answer

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we know that M = m/ n, so we can get nBa(OH)2=m/M
M=137+2.16+2.1=171
m=100g
nBa(OH)2=m/M=100/171=0.58 mole
User Filip Molcik
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