Question

How can i solve this trig identity??

Answer 1

hey there you just need to turn the one into (1+cosx)/(1`+cosx) and go from there 

Answer 2

Additional Information :

• sin² θ + cos² θ = 1
• sin² θ = 1 - cos²θ
• sec²θ = 1 + tan²θ
• cot²θ = cosec²θ - 1

★ Reciprocal identities :-

• 
  `\red{\boxed{sin θ = (1)/(cosecθ)}}`
• 
  `\red{\boxed{cosec θ = (1)/( sin θ)}}`
• 
  `\red{\boxed{cos θ = (1)/( sec θ)}}`
• 
  `\red{\boxed{sec θ = (1)/(cos θ)}}`
• 
  `\red{\boxed{tan θ = (1)/( cot θ)}}`
• 
  `\red{\boxed{cot θ = (1)/(tan θ)}}`