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Your spaceship has docked at a space station above Mars. The temperature inside the space station is a carefully controlled 24 ∘C at a pressure of 745 mmHg . A balloon with a volume of 443 mL drifts into the airlock where the temperature is − 95 ∘C and the pressure is 0.115 atm . What is the final volume, in milliliters, of the balloon if n does not change and the balloon is very elastic?

User Vane
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1 Answer

5 votes
5 votes

Answer: the final volume of the balloon is 2.26 x 10^3 mL

Step-by-step explanation:

The question requires us to determine the new volume of a balloon, given the initial and final conditions.

The following information was provided by the question:

initial temperature = T1 = 24 °C = 297.15 K

initial volume = V1 = 443 mL

initial pressure = P1 = 745 mmHg = 0.980 atm

final temperature = T2 = -95 °C = 178.15 K

final pressure = P2 = 0.115 atm

To solve this problem, we'll need to apply the equation of ideal gases to calculate the number of moles of gas in the balloon, and then use this value and the final temperature and pressure provided to determine the final volume,

The equation of ideal gases can be written as:


PV=nRT

And we can rearrange it to calculate the number of moles:


PV=nRT\rightarrow n=(PV)/(RT)

Applying the values provided by the question:


n=((0.980atm)*(443mL))/(R*(297.15K))=(1.46)/(R)((atm* mL)/(K))

Now, we can rearrange the equation of ideal gases to calculate the volume:


PV=nRT\rightarrow V=(nRT)/(P)

And, applying the values provided and the number of moles as calculated:


V=(((1.46)/(R)atm.mL.K^(-1))* R*(178.15K))/(0.115atm)=2.26*10^3mL

Therefore, the final volume of the balloon is 2.26 x 10^3 mL.

User Jesse Wilson
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