Question

The graph below shows the force required to stretch a spring various distances. Review the graph below.

What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?

Answer 1

Step-by-step explanation:

Elastic string constant (k)

= Slope of the graph F/x

= 15.0N/10.0m = 1.50N/m

Hence,

EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.