Question

Help I have use the calculator in degree mode for this problem

Answer 1

The figure above consists of a triangle and a semi-circle.

Area of the figure = Area the of triangle + Area of the semi-circle

`\begin{gathered} \text{Area of triangle = }(1)/(2)* base\text{ }* height\text{ } \\ \text{base of the triagle = 15 ft} \\ \text{height = }15\text{ ft } \\ \text{Area of triangle = }(1)/(2)*15\text{ }*15 \\ \text{Area of triangle = 112.5 ft}^2 \end{gathered}`
`\begin{gathered} \text{Area of the semi circle = }(1)/(2)*\pi r^2 \\ r,\text{ radius = }(diameter)/(2)\text{ = }(15)/(2)\text{ = 7.5} \\ \text{Area of semi-circle = }(1)/(2)*3.14*7.5^2 \\ \text{Area of semi-circle = }(1)/(2)\text{ }*3.14*56.25\text{ = 88.3125} \end{gathered}`

Area of composite figure = 112.5 + 88.3125 = 200.8125

Therefore the Area of the figure = 200.81 squared feet to the nearest hundredth