Question

Solving systems of equations using substitution 3g-23k=75
2g=8k+28

Answer 1

`3g-23k = 75 2g = 8k+28`

we can start by simplifying the second equation


`2g = 8k + 28 \\ (2g)/(2) = (8k+28)/(2) \\ g = 4k+14`

now insert g into the first equation and simplify


`3(4k+14) - 23k = 75 \\ 12k + 42 - 23k = 75 \\ -11k + 42 = 75 \\ -11k = 33 \\ k = -3`


`g = 4k +14 \\ g = 4(-3) +14 \\ g = -12 + 14 \\ g = 2`

Therefor g = 2, k = -3