Question

SO2Cl2 decomposes in a first-order process with a half-life of 4.88 × 103 s. If the original concentration of SO2Cl2 is 0.011 M, how many seconds will it take for the SO2Cl2 to reach 0.0032 M?

Answer 1

The amount of substance after n half-lives is calculated through the equation,
A(n) = A(0) x (0.5)^t/h
where A(n) is the amount of n half-lives, A(0) is the original amount, t is the total time and h is the half-life.
Substituting the known values,
Basis is 1L,
0.0032 = (0.011) x (0.5)^(t/4.88x10^3s)
The value of t from the generated equation is equal to 8693.0 s or also equal to 8.693 x 10^3 s.