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Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47
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Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47

User Ntalekt
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4 votes
the answer would be y=.79
User Mwardm
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