Question

PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)

An aircraft carries a static charge of 0.75 C. It travels at 235 m/s perpendicular to a
1.9
×
10
−
4
T magnetic field. What magnetic force does an aircraft experience?

Answer 1

`\underline{ \boxed{F_m = 3.35 { * 10}^( - 2) N}}`

Step-by-step explanation:

`since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \: max = qvB \sin(90) \\ F_m = qvB * (1) = qvB \\ hence \to \\ F_m = qvB \\ where \\ \: q = 0.75 C : v = 235m {s}^( - 1) : B = 1.9 { * 10}^( - 4) T \\ therefore \to \\ F_m = 0.75 * 235 * 1.9 { * 10}^( - 4) \\ F_m = 176.25 * 1.9 { * 10}^( - 4) \\ F_m = 0.0334875 = 3.35 { * 10}^( - 2) N \\ \boxed{F_m = 3.35 { * 10}^( - 2) N}`