Question

Suppose that the population of deer in a state is 19900 and is growinh 3% each year. Predict the population after 10 years.

Answer 1

`\bf \qquad \textit{Compound Interest Amount}\\\\ A=P\left(1+(r)/(n)\right)^(nt) \qquad \begin{cases} A=\textit{current amount}\\ P=\textit{original amount }\to &\$19,900\\ r=rate\to 3\%\to (3)/(100)\to &0.03\\ n=\textit{times it compounds per year}\to &1\\ t=years\to &10 \end{cases} \\\\\\ A=19,900\left(1+(0.03)/(1)\right)^(1\cdot 10)`