Question

Subtract 1/6a+3 from 1/3a−5 .

Answer 1

1/3a - 5 - (1/6a + 3) =
1/3a - 5 - 1/6a - 3 =
1/3a - 1/6a - 5 - 3 =
2/6a - 1/6a - 8 =
1/6a - 8 <===

Answer 2

`(3a+8)/(3(2a+1)(3a-5))`

Explanation:

We want to subtract
`(1)/(6a+3)` from
`(1)/(3a-5)`.

We set up the subtraction problem as follows;

`(1)/(3a-5)-(1)/(6a+3)`

We collect LCM of the denominators to obtain

`=(6a+3-(3a-5))/((6a+3)(3a-5))`

Expand the bracket in the numerator to obtain;

`=(6a+3-3a+5)/((6a+3)(3a-5))`

This simplifies to;

`=(3a+8)/(3(2a+1)(3a-5))`