Question

A 1400 kg car is moving at 12 m/s when the driver stops a car what increase in the thermal energy of the car and it surroundings results from a find the brakes to bring the car to a stop

Answer 1

KE = 1/2 1400 (12)^2

KE = 100,800 J

Answer: 1.0 x 10^5 J

Answer 2

KE = 1/2 mv^2

in this case, the initial kinetic energy which is converted to heat is

KE = 1/2 1400 (12)^2

KE = 100,800 J