Solve the system of equations by substitution y=3x-10 3x+2y=16

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asked Oct 16, 2018 134k views

4 votes

Solve the system of equations by substitution y=3x-10 3x+2y=16

Mathematics
middle-school

Gcamp asked

by Gcamp

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1 Answer

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y=3x-10
3x+2y=16

substitute y=3x-10 into 3x+2y=16

3x+2y=16
3x+2(3x-10)=16
3x +6x - 20 = 16
9x = 36
x = 4

y=3x-10
y=3(4)-10
y=12-10
y=2

answer: x =4 and y = 2 or (4,2)

Eunhye answered Oct 20, 2018

by Eunhye

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