Question

Answer 1

`√(x+6) =x-6`

`x+6=(x-6)^2`

`x+6=x^2-12x+36`
Subtract
`x^2-12x+36` from both sides:

`x+6-(x^2-12x+36)=x^2-12x+36-(x^2-12x+36)`

`-x^2+13x-30=0`

`(-x+3)(x-10)=0`

`-x+3=0` or
`x-10=0`
Plug 3 into the equation:

`√(3+6)=3-6`

`3 \\eq -3`
Plug 10 into your equation:

`√(10+6) =10-6`

`4=4`
So, your answer is:

`10`

Good luck with your studies, I hope this helps!~