Question

Weighing 15,000 N is parked on a 10 m2 hydraulic lift platform. What is the area of ​​a small piston if a 1,100 N nozzle is used to lift the vehicle?

Answer 1

`A_2=0.74\ m^2`

Step-by-step explanation:

Given that,

Weight, F₁ = 15,000 N

Area, A₁ = 10 m²

Weight, F₂ = 1100 N

We need to find the area of the small piston. The pressure exerted on both piston will be equal such that,

`(F_1)/(A_1)=(F_2)/(A_2)\\\\A_2=(F_2A_1)/(F_1)\\\\A_2=(1100* 10)/(15000)\\\\A_2=0.74\ m^2`

So, the area of the smaller piston is
`0.74\ m^2`.