Question

the volume v of a fixed amount of a gas variety directly as the temperature T and inversely as the pressure P. suppose that V =42cm3 when T=84 kelvin and P=8kg/cm2 find the temperature when V =74cm3 and P=10 kg/cm2

Answer 1

ok

I'll use the law of gases to solve this problem

V1 = 42 cm^3

T1 = 84 °K

P = 8 Kg/cm^2

T2 = x

V2 = 74 cm^3

P2 = 10 kg/cm^2

Equation

P1V1/T1 = P2V2/T2

Solve for T2

T2 = P2V2T1 / P1V1

Substitution

T2 = (10*74*84) / (8*42)

Simplification

T2 = 62160 / 336

Result

T2 = 185°K