Question

Solve the equation sin (x° - 20°) = cos 42° for x, where 0 < x < 90.

a.62
b.22
c.68
d.28

Answer 1

in my opinion is c

i hope it will help

Answer 2

c.68

Explanation:

We are given that

`sin(x-20)=cos 42^(\circ)` Where 0 <x< 90

We have to solve for x

`sin(x-20)=cos (90-48)`

`sin(x-20)=sin 48`

`cos (90-\theta)=sin\theta`

Cancel sin on both sides then we get

`x-20=48`

`x=48+20=68`

Hence, the value of x=68

Answer:c.68