Question

What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256

Answer 1

x^2+y^2=256

hope this helps :)

Answer 2

3.
`x^2+y^2=256`

Explanation:

We are asked to find the equation of circle, whose center is at the origin (0,0) and whose radius is 16.

We know that standard form of a circle is in form:
`(x-h)^2+(y-k)^2=r^2`, where,

`(h,k)` = Center of circle,

r = Radius of circle.

Upon substituting our given values in standard form of circle, we will get

`(x-0)^2+(y-0)^2=16^2`

`x^2+y^2=256`

Therefore, 3rd option is the correct choice.