Question

HELP ASAP! PLEASE
Solve 1.1(3.4x-2.3)^2=15.5 and write it in ax^2+bx+c=0 form.

Answer 1

12.716x^2 -17.204x -9.681=0

Explanation:

Answer 2

In the normal ax² + bx + c format, this equation is expressed as:

12.716x² - 17.204x + 9.81 = 0

If we solve for x, it is approximately equal to both 178 and -0.43

Explanation:

Let's reformat to ax² + bx + c = 0:

`1.1(3.4x - 2.3)^2 = 15.5\\1.1(11.56x^2 - 15.64x + 5.29) = 15.5\\12.716x^2 - 17.204x + 5.819 = 15.5\\12.716x^2 - 17.204x + 9.81 = 0\\`

And now let's find the value of x

`1.1(3.4x - 2.3)^2 = 15.5\\(3.4x - 2.3)^2 = 15.5 / 1.1\\(3.4x - 2.3)^2 = 14.09\\3.4x - 2.3 = √(14.09)\\3.4x = 2.3 \pm √(14.09)\\x = (2.3 \pm 3.75)/(3.4)\\x = (1.78, -0.43)`