Question

a scientist need to 6000 calories per day. Based on the percentage of total daily calories and the number of calories needed, how many biscuits, packages of pemmican, butter and coco does a person need each day?

Answer 1

Step-by-step explanation:

Given;

We are told that a scientist needs 6000 calories per day.

We are also given a table showing the percentage of daily calories he can get from three types of food.

These are;

`\begin{gathered} Biscuits---40\% \\ pemmican---45\% \\ Butter\text{ }and\text{ }cocoa---15\% \end{gathered}`

Required;

We are required to calculate how many of each type of food he would need to eat each day.

Step-by-step solution;

We shall solve this by first determining how many calories can be gotten from each type of food based on the percentage given. This is calculated below;

`\begin{gathered} Biscuits: \\ 6000*(40)/(100)=2400 \end{gathered}`

This means if he gets 75 calories from one biscuit, then to get 2,400 calories he would have to eat;

`\begin{gathered} 75cal=1b \\ 2400cal=(2400)/(75) \\ 2400cal=32 \end{gathered}`

The scientist would have to eat 32 biscuits to get 2400 calories.

`\begin{gathered} Pemmican: \\ 6000*(45)/(100)=2700 \end{gathered}`

This means if he gets 135 calories from one pack of dried meat, then to get 2700 calories he would have to consume;

`\begin{gathered} 135cal=1pack \\ 2700cal=(2700)/(135) \\ 2700cal=20 \end{gathered}`

Therefore, the scientist would have to eat 20 packs of pemmican to get 2700 calories

`\begin{gathered} Butter\text{ }and\text{ }Cocoa: \\ 6000*(15)/(100)=900 \end{gathered}`

This means if he eats 1 package of Butter and cocoa he gets 225 calories. To get 900 calories he would have to eat;

`\begin{gathered} 225cal=1pack \\ 900cal=(900)/(225) \\ 900cal=4 \end{gathered}`

Therefore, the scientist would have to eat 4 packs of Butter and cocoa.

We now have the summary as follows;

ANSWER:

`\begin{gathered} Biscuits=32 \\ Pemmican=20\text{ }packs \\ Butter\text{ }and\text{ }cocoa=4\text{ }packs \end{gathered}`