Question

If you have 9.3×1026 molecules of iron that rusts, how many molecules of oxygen does it take?

__Fe + __O2 à __Fe2O3

Answer 1

Answer:1.395x10^27 molecules of O2

Step-by-step explanation:

2Fe + 3/2O2 —> Fe2O3

for every 2 atoms of Fe, 1.5 molecules of O2 —> 1.395x10^27