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A lab is growing bacteria in a culture dish. The amount of bacteria in the dish doubles every 3 hours. Initially, there are 500 bacteria in the dish. How many are in the dish after 9 hours A. 4,500 B. 4,000 C. 1,500 D. 13,500

User BSMP
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2 Answers

3 votes
d- 500*3
*3
*3 = 13500
User Ali Ihsan URAL
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2 votes

Answer: B. 4,000

Explanation:

Given: The initial amount of bacteria in the dish A= 500

Since, The amount of bacteria in the dish doubles every 3 hours.

The multiplicative rate of change after every 3 hours = 2

Time period = 3 hours

By exponential function, we have the amount of bacteria after time period 'x' is given by :-


y=Ab^x, where A is the initial amount , b is the multiplicative rate of change in time period x.

Number of 3 hours period in 9 hours = 3

Therefore, x=3

Therefore, the amount of bacteria in the dish after 9 hours is given by :_


y=500(2)^3=500*8=4000

User Axblount
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