Question

A spring with a spring constant of 50 N/m is stretched 15cm. What is the force and energy associated with this stretching?

Answer 1

Data:
F (force) = ? (Newton)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m

Formula:

`F = k*x`

Solving:

`F = k*x`

`F = 50*0.15`

`\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark`

Data:
E (energy) = ? (joule)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m

Formula:

`E = (k*x^2)/(2)`

Solving:(Energy associated with this stretching)

`E = (k*x^2)/(2)`

`E = (50*0.15^2)/(2)`

`E = (50*0.0225)/(2)`

`E = (1.125)/(2)`

`\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark`