124k views
5 votes
For a parallel structure of identical​ components, the system can succeed if at least one of the components succeeds. Assume that components fail independently of each other and that each component has a 0.11

​(a) Would it be unusual to observe one component​ fail?

Would it be unusual to observe two components​ fail?

​(b) What is the probability that a parallel structure with 2 identical components will​ succeed?

The probability that a parallel structure with 2 identical components will succeed is
​(Type an integer or a decimal. Do not​ round.)

​(c) How many components would be needed in the structure so that the probability the system will succeed is greater than​ 0.9999?

​(Round up to the nearest whole​ number.)

User Griotspeak
by
7.9k points

1 Answer

2 votes
1) If you ever come across a situation where components fail independently of each other and that each component has a 0.11 it won'be unsusual because such percent as 11% is quite frequent and common.

2) If two components​ fail, that will definitely be unusual as the percent greatly increases : 11%*11%=1,21% - it is not as common as in previous situation.

3) Here is the way how you can get the
probability that a parallel structure with 2 identical components will succeed :
you have to take the obtained percent away from 100%
100-1,21=98,79

4) The number of
components that will be needed in the structure so that the probability the system will succeed is greater than .9999 is being shown below:

image
then just round it up.
Do hope that will help you!
User Keenora Fluffball
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories