Question

H=K+log(a/c) isolate a

Answer 1

H=k+log(a/c)
H-k = log(a/c)
e^{h-k}=a/c
a = ce^{h-k}

Answer 2

remember some properties
is no base is stated, assume base 10
and

`log_a(b)=c` means
`a^c=b`
and

`a^(log_a(b))=b`
and

`log_a(b/c)=log_a(b)-log_a(c)`
and

`x^(a+b)=(x^a)(x^b)`
so


`H=K+log(a/c)`

`H=K+log_(10)(a/c)`

`H=K+log_(10)(a)-log_(10)(c)`
minus K-log10(c) from both sides

`H-K+log_(10)(c)=log_(10)(a)`
convert

`10^{H-K+log_(10)(c)}=a`

`(10^(H-K)(10^{log_(10)(c)}=a`

`(10^(H-K))(c)=a`

`a=c10^(H-K)`